Water falls through a height of 50m. Determine the temperature rise at the bottom of the fall. [Neglect energy losses. Specific heat capacity of water = 4200Jkg-1 K-1, g = 10ms2]
-
0.119oC
- 0.840oC
- 1.190oC
- 8.400oC
The correct answer is: A
Explanation
mgh = mc\(\theta\)\(\theta = \frac{gh}{c} = \frac{10 \times 50}{4200}\)
= 0.119oC