The distance between two points in phase on a progressive wave is 5cm. If the sped of the wave is 0.2ms-1, calculate its period
- 4.00s
- 2.50s
-
0.25s
- 0.04s
The correct answer is: C
Explanation
F = \(\frac{v}{\lambda} = \frac{0.2}{5 \times 10^{-2}} = 4Hz\)T = \(\frac{1}{f} = \frac{1}{4} = 0.25s\)