Radio waves travel in air at 3.0 x 108ms-1. If the waves enter water of refractive index \(\frac{4}{3}\), calculate the speed of radio waves in water
- 4.33 x 108ms-1
- 4.00 x 108ms-1
-
2.25 x 108ms-1
- 1.33 x 108ms-1
The correct answer is: C
Explanation
\(_an_w = \frac{4}{3} = \frac{\text{speed of light in air}}{\text{speed of light in water}}\)\(\frac{4}{3} = \frac{3 \times 10^8}{x}\)
x = \(\frac{9 \times 10^4}{4}\)
= 2.25 x 108m/s