Two capacitors if capacitance 0.4\(\mu F\) and 0.5\(\mu F\) are connected in parallel and charged to a p.d. of 50V, Determine the total charge acquired
-
45\(\mu C\)
- 25\(\mu C\)
- 20\(\mu C\)
- 10\(\mu C\)
The correct answer is: A
Explanation
C = \(C_1 + C_2\) = 0.4 + 0.5 = 0.9\(\mu F\)Q = Cv = 0.9 x 50 = 45\(\mu C\)