A parallel plate capacitor of capacitance 600\(\mu F\) has a potential difference of 200V between…

Physics WAEC 2005

A parallel plate capacitor of capacitance 600\(\mu F\) has a potential difference of 200V between its plates. Calculate the charge on either plate of the capacitor

  • 1.2C checkmark
  • 3.3C
  • 3330.0C
  • 12.0000.0C

The correct answer is: A

Explanation

Q = CV

= 600 x 10-6 x 200 = 1.2C
Previous Question Next Question

Leave A Comment