a chemical cell of internal resistance 1\(\Omega\) supplies electric current to an external resistor of resistance 3\(\Omega\). Calculate the efficiency of the cell
-
75%
- 50%
- 33%
- 25%
The correct answer is: A
Explanation
R = \(r_1 + R = 1 + 3 = 4\Omega\)\(\frac{3}{4} \times \frac{100}{1} = 75\)%