A ball is projected specific latent heat of ice = 3.4 x 10\(^{2}\) Jg\(^{-1}\) horizontally from a height of 20m above the ground specific heat capacity of water = 4.2 Jg\(^{-1}\) K\(^{-1}\) with an initial velocity of 0.4ms\(^{-1}\). Calculate the horizontal distance moved by the ball before hitting the ground. [g = 10ms\(^{-1}\)]
Explanation
R = \(U\sqrt{\frac{2H}{g}}\)
= 0.4 \(\sqrt{\frac{2 \times 20}{10}}\)
= 0.8m