The equivalent capacitance of a 3\(\mu F\) capacitor and a 6\(\mu F\) capacitor connected in parallel is
- 2.0\(\mu F\)
- 3.0\(\mu F\)
- 4.5\(\mu F\)
-
9.0\(\mu F\)
The correct answer is: D
Explanation
C = C1 + C2= 3 + 6 = 9\(\mu F\)