An external force of magnitude 100N acts on a particle of mass 0.15kg for 0.03s. Calculate the change in the speed of the particle
- 50ms-1
- 25ms-1
-
20ms-1
- 5ms-1
The correct answer is: C
Explanation
a = \(\frac{F}{m} = \frac{100}{0.15} = 666.7\)v = u + at
= 0 + 66.7 x 0.03
= 20m/s2