A plane inclined at 30o to the horizontal has an efficiency of 50%. Calculate the force parallel to the plane required to push a load of 120N uniformly upn the plane
- 50.0N
-
120.0N
- 200.0N
- 240N
The correct answer is: B
Explanation
V.R = \(\frac{1}{sin\theta} = \frac{1}{sin 30} = 2\)M.A = \(\frac{E \times V.R}{100} = \frac{50 \times 2}{100} = 1\)
Effort = \(\frac{load}{M.A} = \frac{120}{1} = 120N\)