The distance between a concave mirror and an object placed in front of it is 1.0m. If the raduis of curvature of the mirror is 4.0m, the image formed will be
- 2.00m behind the mirror
-
2.00m in front of the mirror
- 1.25m in front of the mirror
- 1.25m behind the mirror
The correct answer is: B
Explanation
The focal length of a concave mirror is negative
f = -2m
\(\frac{1}{f} = \frac{1}{v} + \frac{1}{u}\)
\(\frac{1}{-2} = \frac{1}{v} - \frac{1}{1}\)
\(\frac{1}{v} = \frac{1}{-2} + \frac{1}{1}\)
\(\frac{1}{v} = \frac{1}{2}\)
v = 2m
The image distance is 2.0 m in front of the mirror