A direct current of 5A flow through a 0.2H inductor. Calculate the energy stored in the inductor
- 0.5J
- 1.0J
-
2.5J
- 5.0J
The correct answer is: C
Explanation
P = \(\frac{1}{2} I^2 L\)
= 5\(^2 \times\) 0.2 \(\times\) \(\frac{1}{2}\)
= 2.5J