A body of volume 0.046m3 is immersed in a liquid of density 980kgm-3 with \(\frac{3}{4}\) of its volume submerged. Calculate the upthrust on the body. [g = 10ms-2]
- 11.27N
- 33.81N
- 112.70N
-
338.10N
The correct answer is: D
Explanation
M = D x V= 980 x 0.046 x \(\frac{3}{4}\) = 33.81kg
upthrust = mg = 33.81 x 10
= 338.1N