A rod of initial lenght 2m at a temperature of 25oC is heated to 80oC. Calculate the increase in length of the rod if its linear expansivity is 4.0 x 10-3K-1
- 0.26m
-
0.44m
- 0.53m
- 0.84m
The correct answer is: B
Explanation
\(l_2 - l_1 = \alpha l_1 (\theta_2 - \theta_1) = 4.0 \times 10^{-3} \times 2(80 - 25)\)= 0.44m