A wire of resistivity 4.40 x 10-5\(\Omega\) cm has a cross sectional area of 7.50…

Physics WAEC 2009

A wire of resistivity 4.40 x 10-5\(\Omega\) cm has a cross sectional area of 7.50 x 10-4 cm2. Calculate the length of the wire that will be required to make a 4.0\(\Omega\) resistor

  • 82.50 cm
  • 68.18cm checkmark
  • 15.90cm
  • 11.95cm

The correct answer is: B

Explanation

L = \(\frac{R.A}{e} = \frac{4 \times 7.50 \times 106{-4}}{4.40 \times 10^{-5}} = 68.18cm\)
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