simple harmonic oscillator has a period of 0.02s and amplitude of 0.25m. Calculate the speed…

Physics WAEC 2010

simple harmonic oscillator has a period of 0.02s and amplitude of 0.25m. Calculate the speed in ms-1 at the centre of the oscillation

  • 125\(\pi\)
  • 25.00\(\pi\) checkmark
  • 100.00 \(\pi\)
  • 400.00\(\pi\)

The correct answer is: B

Explanation

V = WX = \(\frac{2\pi \times 0.25}{0.02} = 25\pi\)
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