A galvanometer of internal resistance 50\(\Omega\) and full scale deflection of 20 mA is converted…

Physics WAEC 2010

A galvanometer of internal resistance 50\(\Omega\) and full scale deflection of 20 mA is converted into a voltmeter by connecting a resistor of resistance 1950\(\Omega\) in series to it. Calculate the maximum voltage that can be read by the voltmeter

  • 20V
  • 30V
  • 38V
  • 40V checkmark

The correct answer is: D

Explanation

V = IR1 + IR2

= 0.02 x 50 + 0.02 x 1950 = 40V
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