An X-ray tube operates at a potential of 2500 V. If the power of the tube is 750 W, calculate the speed of the electron striking the target. [e = 1.6 x 10\(^{-19}\) C; mass of electron = 9.1 x 10\(^{-3}\) kg]
Explanation
(a) eV \(\frac{1}{2}MV^2\)
V\(^2 = \frac{2eV}{m}\)
= \(\frac{2 \times 1.6 \times 10^{-19} \times 2500}{9.1 \times 10^{-31}}\)
V = \(\sqrt{8.79 \times 10^{14}}\)
= 2.96 x 10\(^{7}\)