A metal rod of density 7000 kgm-3 and cross-sectional area of 0.001257m2 has a mass of 1.76kg. Calculate its length.
-
0.20m
- 0.25m
- 0.40m
- 0.50m
The correct answer is: A
Explanation
P = \(\frac{M}{AL}\)L = \(\frac{M}{CA}\)
= \(\frac{1.76}{7000 \times 0.001257}\)
= 0.2m