A coin is pushed from the edge of a laboratory bench with a horizontal velocity of 15.0 ms-1. If the height of the bench from the floor is 1.5m, calculate the distance from the foot of the bench to the point of impact with the floor [g = 10ms-2]
- 0.75m
- 2.25m
-
8.22m
- 15.00m
The correct answer is: C
Explanation
S = U\(\sqrt{\frac{2h}{g}}\)= 15\(\sqrt{\frac{2 \times 1.5}{10}}\)
= 8.22m