The radius of a wheel is 30.0 cm and that of its axle is 6.0cm. Calculate the effort required to lift a load of 120.0N using this machine. Assuming 100% efficiency
- 600.0N
- 40.0N
-
24.0N
- 20.0N
The correct answer is: C
Explanation
V.R = \(\frac{R}{r} = \frac{30}{6} = 5\)\(\gamma = \frac{M.A}{V.R} \times \frac{100}{1} \)
M.A = \(\frac{100 \times 5}{100} = 5\)
Effort = \(\frac{L}{M.A} = \frac{120}{5}\)
= 24N