Using the circuit diagram above. Calculate the total charge in the circuit

Explanation

C - \(C_1 + C_2 = 2 + 6 = \mu F\)

\(\frac{1}{C} = \frac{1}{C_1} + \frac{1}{C_1} + \frac{1}{C_2} = \frac{1}{8} + \frac{1}{2}\)

C = \(\frac{8}{5 \mu F}\)

Q = CV

= \(\frac{8}{5} \times 10 = 16\mu C\)