A 12\(\Omega\) resistor dissipates 8kJ of heat in 20s. Calculate the current through the resistor
-
5.8A
- 6.9A
- 30.0A
- 33.3A
The correct answer is: A
Explanation
Q = I2Rt
I = \(\sqrt{\frac{Q}{Rt}}\)
= \(\sqrt{\frac{8000}{12 \times 20}}\)
= 5.8