An inductor is connected to a 24V, 50Hz mains supply. If the current through the inductor is 1.5A, calculate the inductance of the inductor (\(\pi = \frac{22}{7}\))
- 8.0 x 102H
- 7.5 x 10oH
- 1.6 x 10oH
-
5.1 x 10-2H
The correct answer is: D
Explanation
\(X_L = \frac{V}{I} = \frac{24}{1.5} = 16\Omega\)L = \(\frac{XL}{2 \pi f} = \frac{16}{2 \pi 50}\)
= 0.05H