A spiral spring with a metal extends by 10.5 cm in air. When the metal is fully submerged in water, the spring extends by 6.8 cm. Calculate the relative density of the metal. (Assume Hooke’s law is obeyed)
Explanation
R.d = \(\frac{\text{weight of object in air}}{\text{upthrust in water}}\)
= \(\frac{10.5}{10.5 - 6.8} = \frac{10.5}{3.7} = 2.84\)