A body of mass 2kg is released from rest on a plane inclined at an angle of 60° to the horizontal. Calculate the acceleration of the body down the plane.[g = 10ms\(^{-2}\)]
- 3.1ms-2
- 5.2ms-2
- 6.0ms-2
-
8.7ms-2
The correct answer is: D
Explanation
a = g sin \(\theta\)
= 10 sin 60
= 8.7 ms\(^{-2}\)