A body of mass 20g projected vertically upwards in vacuum returns to the point of projection after 1.2s. [g = 10ms-2]. Determine the potential energy of the body at the maximum height of its motion
-
0.36J
- 0.72J
- 360.00J
- 720.00J
The correct answer is: A
Explanation
P.E at max = K.E on projection= \(\frac{1}{2}\)mv2 = \(\frac{1}{2} \times 0.02 \times 6^2 = 0.36J\)