Ice of mass 10g at 5°C was completely converted to water at 0°C, calculate the quantity of heat used. [specific heat capacity of ice = 2.1 Jg\(^{-1}\)K\(^{-1}\), specific latent heat of fusion of ice = 336 Jg\(^{-1}\)]
- 105J
- 3255J
-
3465J
- 16821J
The correct answer is: C
Explanation
Q = ML + MC\(\theta\)
= 10 x 335 + 10 x 2.1 x 5
= 3465J