A charge of 2.0 x 10\(^{-5}\) C experiences a force of 80N in a uniform electric field. Calculate the magnitude of the electric field intensity
- 8.0 x 106 NC-1
-
4.0 x 106 NC-1
- 4.0 x 104 NC-1
- 2.0 x 104 NC-1
The correct answer is: B
Explanation
E = \(\frac{F}{Q} = \frac{80}{2 \times 10^{-5}}\)
= 4 x 10\(^6\) NC\(^{-1}\)