A potential difference of 12V is applied across the ends of a 6\(\Omega\) resistor for 10 minutes. Determine the quantity of heat generated
- 720J
- 1200J
-
14400J
- 43200J
The correct answer is: C
Explanation
Q = \(\frac{V^2 t}{R}
= \frac{12^2 \times 10 \times 60}{6}\)
= 14400J