A block of wood of mass 5kg is pulled on a platform by a force of 40N as illustrated in the diagram above. If the frictional force, F experienced by the block is 12N, calculate the magnitude of the acceleration of the acceleration of the block
- 2.4ms-2
-
5.6ms-2
- 8.0ms-2
- 2.4ms2
The correct answer is: B
Explanation
F + Ma = P
a = \(\frac{P - F}{m}\)
= \(\frac{40 - 12}{5} = 5.6ms^{-2}\)