A car starts from rest and covers a distance of 40m in 10s. Calculate the magnitude of its acceleration
- 0.25ms-2
-
0.80ms-2
- 3.20ms-2
- 4.00ms-2
The correct answer is: B
Explanation
S = ut + \(\frac{1}{2} at^2\)40 = 0 x 10 + \(\frac{1}{2}\) x a x 102
50a = 40
a = \(\frac{40}{50}\)
= 0.8ms-2