A car traveling at 30ms\(^{-1}\) overcomes a frictional resistance of 100N while moving. Calculate the power developed by the engine. [1 hp = 0.75 kW]
- 0.23hp
- 0.40hp
-
4.00hp
- 4.40hp
The correct answer is: C
Explanation
P = FV = \(\frac{100 \times 30}{1000} = 3 kW\)
\(\frac{3}{0.75} = 4hp\)