an observer hears an echo 1.26 seconds after blowing a whistle near a cliff. calculate…

Physics WAEC 2014

an observer hears an echo 1.26 seconds after blowing a whistle near a cliff. calculate the distance of the observer from the cliff. [speed of sound in air = 330ms-1]

  • 104.4m
  • 207.9m checkmark
  • 415.8m
  • 523.8m

The correct answer is: B

Explanation

S = \(\frac{vt}{2} = \frac{330 \times 1.26}{2} = 207.9\)
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