A 15 \(\mu F\) capacitor is connected to a 240V, 50Hz ac. source. Calculate the reactance of the capacitance [\(\pi = 3.142\)]
- 16\(\Omega\)
- 68\(\Omega\)
- 106\(\Omega\)
-
212\(\Omega\)
The correct answer is: D
Explanation
\(X_c = \frac{1}{2 \pi fc}\)= 2 x 3.142 x 50 x 15 x 10-6
= 212.179\(\Omega\)