A swimming pool is 2.1m deep. If it contains water of refractive index 1.3, calculate the apparent depth of pool
- 3.4m
- 2.7m
-
1.6m
- 0.8m
The correct answer is: C
Explanation
n = \(\frac{\text{real depth}}{\text{apparent depth}}\)
1.3 = \(\frac{2.1}{\text{apparent}}\)
A.D = \(\frac{2.1}{1.3} = 1.6\)