An electric generator rated 12 kW, 2 kV distribute power through a cable of resistance 20\(\Omega\). Calculate the power loss in the cable.
- 120 w
- 360 w
-
720 w
- 2400 w
The correct answer is: C
Explanation
Power - IV
I = \(\frac{P}{V}\)
= \(\frac{12000}{2000}\)
I = 6A
Power loss = I\(^2\)R = 6\(^2\) x 20
= 720 W