A wire of cross-sectional area 0.60mm2 has a restivity of 7.2 x 10-7 \(\Omega\). Calculate the length of wire that will have a resistance of 3\(\Omega\).
- 0.25m
-
2.50m
- 3.60m
- 36.00
The correct answer is: B
Explanation
R = \(\frac{PL}{A}\)C = \(\frac{RA}{P}\)
C = \(\frac{0.60 \times 10^{-6} \times 3}{7.2 \times 10^{-7}}\)
C = 2.50m