in a nuclear fission process, the mass defect was 1.2 x 10-5kg. Calculate the energy released. [speed of the light in vacuum = c = 3.0 x 108ms-1]
- 1.08 x 1011J
- 5.20 x 1011J
-
1.08 x 1012J
- 2.50 x 1013J
The correct answer is: C
Explanation
E - Mec2E = 1.2 x 10-5 x (3 x 108)2
E = 1.08 x 1012J