\(^{226}_{88}Ra\) emits two alpha particles to produce polonium(po) nuclide. The correct formula for the nuclide?

Physics WAEC 2015

\(^{226}_{88}Ra\) emits two alpha particles to produce polonium(po) nuclide. The correct formula for the nuclide?

  • \(^{224}_{86}po\)
  • \(^{222}_{86}po\)
  • \(^{222}_{84}po\)
  • \(^{218}_{84}po\) checkmark

The correct answer is: D

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