At a birthday party, the celebrant pops a corked fruit wine. If the cork shoots out of the bottle at an angle of 40o to the horizontal and travels a horizontal distance of 4.50m in 1.25s. Calculate the initial speed of the cork.
- 4.2ms-1
-
4.7ms-1
- 5.6ms-1
- 7.1ms-1
The correct answer is: B
Explanation
R = Ucos\(\theta\) x tU = \(\frac{R}{Cos \theta \times t}\)
= \(\frac{4.50}{Cos40N.25}\)
= 4.699m/s