An aluminium rod of length 1.8m at 10°C is heated to proceed produce a difference in length of 0.007m. Calculate the temperature to which it is heated. (Linear expansivity of aluminium = 2.3 x 10\(^{-5}\)K\(^{-1}\)
- 155oC
- 160oC
- 169oC
-
179oC
The correct answer is: D
Explanation
\(\alpha = \frac{L_2 - L_1}{L_1(\theta_2 - \theta_1)}\)
L\(_2\) - L\(_1\) = \(\alpha L_1 (\theta_2 - \theta_1)\)
\(\theta_2 = \frac{0.007}{2.3 \times 10^{-5} \times 1.8}\) + 10
= 179°C