The distance between two successive trough of a wave is 0.4m. If the frequency of the source is 825Hz, Calculate the speed of the wave
- 165.0 ms-1
-
330.0ms-1
- 41.5ms-1
- 85.0ms-1
The correct answer is: B
Explanation
v = f\(\lambda\)= 825 x 0.4
= 330.0ms-1