An astronomical telescope has objectives and eye-piece lenses of focal length 3.5m and 5cm respectively. Determine the magnifying power of the telescope when in normal adjustment
-
70.0
- 17.5
- 7.0
- 0.7
The correct answer is: A
Explanation
Magnify power = \(\frac{f_o}{f_e}\)= \(\frac{3.5 \times 100}{5.0}\)
= 70