The p.d across a parallel-plate capacitor is 103V. If the distance between the two plates is 10cm. Calculate the magnitude of the electric field strength between the plates.
-
1.0 x 104Vm-1
- 1.0 x 105Vm-1
- 1.5 x 105Vm-1
- 2.0 x 105Vm-1
The correct answer is: A
Explanation
E = \(\frac{v}{d} = \frac{10^3}{0.1}\)= 10000
= 1.0 x 104Vm-1