A wire of length 400cm is stretched between two fixed points. When plucked, its fundamental frequency is 150Hz. Calculate the speed of the wave produced.
- 250\(ms^{-1}\)
- 625\(ms^{-1}\)
-
1200\(ms^{-1}\)
- 1500\(ms^{-1}\)
The correct answer is: C
Explanation
The fundamental frequency \((f_{0})\) = \(\frac{v}{2l}\)
\(f_{0} = 150Hz; l =400cm = 4m\)
\(150 = \frac{v}{2\times 4}\)
\(v = 150 \times 8 = 1200ms^{-1}\)