A nuclide is represented by \(_{32}^{70}B\). Determine its neutron-proton ratio
- 0.5
- 0.8
-
1.2
- 1.5
The correct answer is: C
Explanation
The element B has a mass number of 70 with atomic number 32. Hence, B has 32 protons and (70-32) = 38 neutrons.
The neutron- proton ratio is 38:32 = \(\frac{38}{32} = 1.1875\)
\(\approxeq 1.2\)