A stone of mass 20g is released from a catapult whose rubber is stretched through 5cm. If the force constant of the rubber is 200Nm\(^{-1}\), calculate the speed with which the stone leaves the catapult.
Explanation
ยฝKe\(^{2}\) = ยฝmv\(^{6}\)
ยฝ x 200 x (0.05)\(^{2}\) = ยฝ x 0.02 x v\(^{2}\)
v\(^{2}\) = 25
v = 5 m s\(^{-1}\)