A current of 2A passes through a wire of resistance 4Ω for 3 minutes. Calculate the energy lost.
- 960J
- 1440J
-
2880J
- 48J
The correct answer is: C
Explanation
Power = current[I]\(^2\) * Resistance[R] → 2\(^2\) * 4 → 4 * 4 = 16watts
time = 3minutes → 3 * 60 = 180s
Energy = power * time → 16 * 180 = 2880j