The sketched graph above represents a progressive wave moving from the left to the right. The period of the wave is 0.125s.
Determine the values of the amplitude and wavelength, respectively, of the wave.
The correct answer is: B
Explanation
Amplitude = 16cm/2 = 8cm ( displacement from mean position)
3\(\lambda\) = 27cm
\(\lambda\) = \(\frac{27}{3}\) = 9cm
Therefore, amplitude(A) = 8cm and \(\lambda\) = 9cm